two different calendars on same web page ???

[Cappiels]

I am running two copies of the calendar.. each with a different mySQL database.

I'd like to display the data from BOTH calendars on one web page.

Could someone share with me how to do that.. (because the code on my web page currently would have no way of determining which calendar it was looking at.

<?php $OL=1; require ("showCalendar.php"); ?>
          </p>
        </div>
        <table align="center">
          <tr>
            <td><?php require ("showCalendar.php"); ?>
            </td>
            <td width="0" align="left" valign="top"><a name="escOL">&nbsp;</a> </td>
          </tr>
        </table>
        <div align="center"></div>
        <p align="center"><span class="style4">&nbsp;&nbsp;&nbsp;&nbsp;</span><a href="http://mskweb3.mskcc.org/eday/index.cfm?CalendarID=3"><br>
          </a></p>
      </div></td>
      <td width="256" valign="top"><div align="right">
          <p><span class="style4"><a href="http://rta.mskcc.org/rta/escal_rec/body.php">SKI Recruitment Calendar</a>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<a href="http://mskweb3.mskcc.org/eday/index.cfm?CalendarID=3"><br>
      RTA Vacation calendar</a>&nbsp;&nbsp;&nbsp;&nbsp; <br>
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<a href="FMP7://140.163.188.196/RTDB.fp7">RTA Database System</a>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</span><a href="http://mskweb3.mskcc.org/eday/index.cfm?CalendarID=3"><br>
    </a></p>
      </div></td>
    </tr>
  </table>
  <div align="center">
    <p align="center"><span class="style3 style1"><span class="style4">Upcoming week:</span><br>
          <br>
      </span>
        <?php
$LIST=1;
$listWeeks = 1;
$DF = "D - M d"; 
$template="monthly.php"; 
require ("showCalendar.php"); 
?>

[Brian]

The current version is not designed to do this and would not work without major modifications.

<adding to wish list...>

[Cappiels]

I suppose I could achieve something close to this by creating a web page with a left and a right frame... and then calling each page separately from it's current (working) location..

ya think ???

[Brian]

I believe that would work for this particular application.